Optimal. Leaf size=361 \[ \frac {2 b \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (24 a^2 C+143 a b B+99 A b^2+81 b^2 C\right )}{693 d}+\frac {2 F\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \left (77 a^3 B+33 a^2 b (7 A+5 C)+165 a b^2 B+5 b^3 (11 A+9 C)\right )}{231 d}+\frac {2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \left (3 a^3 (5 A+3 C)+27 a^2 b B+3 a b^2 (9 A+7 C)+7 b^3 B\right )}{15 d}+\frac {2 \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x) \left (24 a^3 C+242 a^2 b B+33 a b^2 (9 A+7 C)+77 b^3 B\right )}{495 d}+\frac {2 \sin (c+d x) \sqrt {\cos (c+d x)} \left (77 a^3 B+33 a^2 b (7 A+5 C)+165 a b^2 B+5 b^3 (11 A+9 C)\right )}{231 d}+\frac {2 (6 a C+11 b B) \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2}{99 d}+\frac {2 C \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3}{11 d} \]
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Rubi [A] time = 0.92, antiderivative size = 361, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.163, Rules used = {3049, 3033, 3023, 2748, 2639, 2635, 2641} \[ \frac {2 F\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \left (33 a^2 b (7 A+5 C)+77 a^3 B+165 a b^2 B+5 b^3 (11 A+9 C)\right )}{231 d}+\frac {2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \left (3 a^3 (5 A+3 C)+27 a^2 b B+3 a b^2 (9 A+7 C)+7 b^3 B\right )}{15 d}+\frac {2 b \sin (c+d x) \cos ^{\frac {5}{2}}(c+d x) \left (24 a^2 C+143 a b B+99 A b^2+81 b^2 C\right )}{693 d}+\frac {2 \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x) \left (242 a^2 b B+24 a^3 C+33 a b^2 (9 A+7 C)+77 b^3 B\right )}{495 d}+\frac {2 \sin (c+d x) \sqrt {\cos (c+d x)} \left (33 a^2 b (7 A+5 C)+77 a^3 B+165 a b^2 B+5 b^3 (11 A+9 C)\right )}{231 d}+\frac {2 (6 a C+11 b B) \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2}{99 d}+\frac {2 C \sin (c+d x) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3}{11 d} \]
Antiderivative was successfully verified.
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Rule 2635
Rule 2639
Rule 2641
Rule 2748
Rule 3023
Rule 3033
Rule 3049
Rubi steps
\begin {align*} \int \sqrt {\cos (c+d x)} (a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx &=\frac {2 C \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{11 d}+\frac {2}{11} \int \sqrt {\cos (c+d x)} (a+b \cos (c+d x))^2 \left (\frac {1}{2} a (11 A+3 C)+\frac {1}{2} (11 A b+11 a B+9 b C) \cos (c+d x)+\frac {1}{2} (11 b B+6 a C) \cos ^2(c+d x)\right ) \, dx\\ &=\frac {2 (11 b B+6 a C) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{99 d}+\frac {2 C \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{11 d}+\frac {4}{99} \int \sqrt {\cos (c+d x)} (a+b \cos (c+d x)) \left (\frac {3}{4} a (33 a A+11 b B+15 a C)+\frac {1}{4} \left (198 a A b+99 a^2 B+77 b^2 B+150 a b C\right ) \cos (c+d x)+\frac {1}{4} \left (99 A b^2+143 a b B+24 a^2 C+81 b^2 C\right ) \cos ^2(c+d x)\right ) \, dx\\ &=\frac {2 b \left (99 A b^2+143 a b B+24 a^2 C+81 b^2 C\right ) \cos ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{693 d}+\frac {2 (11 b B+6 a C) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{99 d}+\frac {2 C \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{11 d}+\frac {8}{693} \int \sqrt {\cos (c+d x)} \left (\frac {21}{8} a^2 (33 a A+11 b B+15 a C)+\frac {9}{8} \left (77 a^3 B+165 a b^2 B+33 a^2 b (7 A+5 C)+5 b^3 (11 A+9 C)\right ) \cos (c+d x)+\frac {7}{8} \left (242 a^2 b B+77 b^3 B+24 a^3 C+33 a b^2 (9 A+7 C)\right ) \cos ^2(c+d x)\right ) \, dx\\ &=\frac {2 \left (242 a^2 b B+77 b^3 B+24 a^3 C+33 a b^2 (9 A+7 C)\right ) \cos ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{495 d}+\frac {2 b \left (99 A b^2+143 a b B+24 a^2 C+81 b^2 C\right ) \cos ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{693 d}+\frac {2 (11 b B+6 a C) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{99 d}+\frac {2 C \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{11 d}+\frac {16 \int \sqrt {\cos (c+d x)} \left (\frac {231}{16} \left (27 a^2 b B+7 b^3 B+3 a^3 (5 A+3 C)+3 a b^2 (9 A+7 C)\right )+\frac {45}{16} \left (77 a^3 B+165 a b^2 B+33 a^2 b (7 A+5 C)+5 b^3 (11 A+9 C)\right ) \cos (c+d x)\right ) \, dx}{3465}\\ &=\frac {2 \left (242 a^2 b B+77 b^3 B+24 a^3 C+33 a b^2 (9 A+7 C)\right ) \cos ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{495 d}+\frac {2 b \left (99 A b^2+143 a b B+24 a^2 C+81 b^2 C\right ) \cos ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{693 d}+\frac {2 (11 b B+6 a C) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{99 d}+\frac {2 C \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{11 d}+\frac {1}{15} \left (27 a^2 b B+7 b^3 B+3 a^3 (5 A+3 C)+3 a b^2 (9 A+7 C)\right ) \int \sqrt {\cos (c+d x)} \, dx+\frac {1}{77} \left (77 a^3 B+165 a b^2 B+33 a^2 b (7 A+5 C)+5 b^3 (11 A+9 C)\right ) \int \cos ^{\frac {3}{2}}(c+d x) \, dx\\ &=\frac {2 \left (27 a^2 b B+7 b^3 B+3 a^3 (5 A+3 C)+3 a b^2 (9 A+7 C)\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{15 d}+\frac {2 \left (77 a^3 B+165 a b^2 B+33 a^2 b (7 A+5 C)+5 b^3 (11 A+9 C)\right ) \sqrt {\cos (c+d x)} \sin (c+d x)}{231 d}+\frac {2 \left (242 a^2 b B+77 b^3 B+24 a^3 C+33 a b^2 (9 A+7 C)\right ) \cos ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{495 d}+\frac {2 b \left (99 A b^2+143 a b B+24 a^2 C+81 b^2 C\right ) \cos ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{693 d}+\frac {2 (11 b B+6 a C) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{99 d}+\frac {2 C \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{11 d}+\frac {1}{231} \left (77 a^3 B+165 a b^2 B+33 a^2 b (7 A+5 C)+5 b^3 (11 A+9 C)\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx\\ &=\frac {2 \left (27 a^2 b B+7 b^3 B+3 a^3 (5 A+3 C)+3 a b^2 (9 A+7 C)\right ) E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{15 d}+\frac {2 \left (77 a^3 B+165 a b^2 B+33 a^2 b (7 A+5 C)+5 b^3 (11 A+9 C)\right ) F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{231 d}+\frac {2 \left (77 a^3 B+165 a b^2 B+33 a^2 b (7 A+5 C)+5 b^3 (11 A+9 C)\right ) \sqrt {\cos (c+d x)} \sin (c+d x)}{231 d}+\frac {2 \left (242 a^2 b B+77 b^3 B+24 a^3 C+33 a b^2 (9 A+7 C)\right ) \cos ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{495 d}+\frac {2 b \left (99 A b^2+143 a b B+24 a^2 C+81 b^2 C\right ) \cos ^{\frac {5}{2}}(c+d x) \sin (c+d x)}{693 d}+\frac {2 (11 b B+6 a C) \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{99 d}+\frac {2 C \cos ^{\frac {3}{2}}(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{11 d}\\ \end {align*}
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Mathematica [A] time = 1.92, size = 285, normalized size = 0.79 \[ \frac {10 F\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \left (77 a^3 B+33 a^2 b (7 A+5 C)+165 a b^2 B+5 b^3 (11 A+9 C)\right )+154 E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \left (3 a^3 (5 A+3 C)+27 a^2 b B+3 a b^2 (9 A+7 C)+7 b^3 B\right )+\frac {1}{12} \sin (c+d x) \sqrt {\cos (c+d x)} \left (154 \cos (c+d x) \left (36 a^3 C+108 a^2 b B+3 a b^2 (36 A+43 C)+43 b^3 B\right )+5 \left (1848 a^3 B+36 b \cos (2 (c+d x)) \left (33 a^2 C+33 a b B+11 A b^2+16 b^2 C\right )+396 a^2 b (14 A+13 C)+154 b^2 (3 a C+b B) \cos (3 (c+d x))+5148 a b^2 B+3 b^3 (572 A+531 C)+63 b^3 C \cos (4 (c+d x))\right )\right )}{1155 d} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.71, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (C b^{3} \cos \left (d x + c\right )^{5} + {\left (3 \, C a b^{2} + B b^{3}\right )} \cos \left (d x + c\right )^{4} + A a^{3} + {\left (3 \, C a^{2} b + 3 \, B a b^{2} + A b^{3}\right )} \cos \left (d x + c\right )^{3} + {\left (C a^{3} + 3 \, B a^{2} b + 3 \, A a b^{2}\right )} \cos \left (d x + c\right )^{2} + {\left (B a^{3} + 3 \, A a^{2} b\right )} \cos \left (d x + c\right )\right )} \sqrt {\cos \left (d x + c\right )}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{3} \sqrt {\cos \left (d x + c\right )}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 2.86, size = 1082, normalized size = 3.00 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} {\left (b \cos \left (d x + c\right ) + a\right )}^{3} \sqrt {\cos \left (d x + c\right )}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.80, size = 514, normalized size = 1.42 \[ \frac {2\,\left (A\,a^3\,\mathrm {E}\left (\frac {c}{2}+\frac {d\,x}{2}\middle |2\right )+A\,a^2\,b\,\mathrm {F}\left (\frac {c}{2}+\frac {d\,x}{2}\middle |2\right )+A\,a^2\,b\,\sqrt {\cos \left (c+d\,x\right )}\,\sin \left (c+d\,x\right )\right )}{d}+\frac {B\,a^3\,\left (\frac {2\,\sqrt {\cos \left (c+d\,x\right )}\,\sin \left (c+d\,x\right )}{3}+\frac {2\,\mathrm {F}\left (\frac {c}{2}+\frac {d\,x}{2}\middle |2\right )}{3}\right )}{d}-\frac {2\,A\,b^3\,{\cos \left (c+d\,x\right )}^{9/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {9}{4};\ \frac {13}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{9\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {2\,C\,a^3\,{\cos \left (c+d\,x\right )}^{7/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {7}{4};\ \frac {11}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{7\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {2\,B\,b^3\,{\cos \left (c+d\,x\right )}^{11/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {11}{4};\ \frac {15}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{11\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {2\,C\,b^3\,{\cos \left (c+d\,x\right )}^{13/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {13}{4};\ \frac {17}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{13\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {6\,A\,a\,b^2\,{\cos \left (c+d\,x\right )}^{7/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {7}{4};\ \frac {11}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{7\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {6\,B\,a^2\,b\,{\cos \left (c+d\,x\right )}^{7/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {7}{4};\ \frac {11}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{7\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {2\,B\,a\,b^2\,{\cos \left (c+d\,x\right )}^{9/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {9}{4};\ \frac {13}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{3\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {2\,C\,a^2\,b\,{\cos \left (c+d\,x\right )}^{9/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {9}{4};\ \frac {13}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{3\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}}-\frac {6\,C\,a\,b^2\,{\cos \left (c+d\,x\right )}^{11/2}\,\sin \left (c+d\,x\right )\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{2},\frac {11}{4};\ \frac {15}{4};\ {\cos \left (c+d\,x\right )}^2\right )}{11\,d\,\sqrt {{\sin \left (c+d\,x\right )}^2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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